InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If `a+b-c=14` then find the value of `2b^2c^2+2c^2a^2+2a^2b^2-a^4-b^4-c^4` |
|
Answer» `=4a^2b^2-(a^4+b^4+c^4-2c^2a^2-2b^2c^2+2a^2b^2)` `=(2ab)^2-(a^2=b^2-c^2)^2` `=(2ab-(a^2+b^2-c^2))(2ab+a^2+b^2-c^2)` `=(2ab-a^2-b^2+c^2)(2ab+a^2+b^2-c^2)` `=(c^2-(a-b)^2)((a+b)^2-c^2)` `=(c-(a-b))(c+(a-b))((a+b)-c)(a+b+c)` `=(c-a+b)(c+a-b)(a+b-c)(a+b+c)` `a+b-c=14` `14(c-a+b)(c+a-b)(a+b+c)` `a=7,b=7,c=0`. |
|