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If a,b,c are in AP and `(a+2b-c)(2b+c-a)(c+a-b)=lambdaabc`, then `lambda` isA. 1B. 2C. 4D. None of these |
Answer» Correct Answer - C `:.a,b,c` are in AP. `:. 2b=a+c" " "…..(i)"` Now, `(a+2b-c)(2b+c-a)(c+a-b)` `(a+a+c-c)(a+c+c-a)(2b-b)" " [" from Eq.(i) "]` `=(2a)(2c)(b)=4abc` `:. Lambda =4`. |
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