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If a, b, c are in GP, then show that log an , log bn , log cn are in AP. |
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Answer» To prove: log an , log bn , log cn are in AP. Given: a, b, c are in GP Formula used: log ab = log a + log b As a, b, c are in GP ⇒ b2 = ac Taking power n on both sides ⇒ b2n = (ac)n Taking log both side ⇒ logb2n = log(ac)n ⇒ logb2n = log(ancn) ⇒ 2logbn = log(an) + log(cn) Whenever a,b,c are in AP then 2b = a+c, considering this and the above equation we can say that log an, log bn, log cn are in AP. Hence Proved |
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