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If a, b, c are in HP, then `(a-b)/(b-c)` is equal to |
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Answer» Since, `a,b,c` are in HP, therefore `(1)/(a),(1)/(b),(1)/(c)` are in AP `i.e.(1)/(b)-(1)/(a)=(1)/(c)-(1)/(b)` or `(a-b)/(ab)=(b-c)/(bc)" or "(a-b)/(b-c)=(a)/(c)` |
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