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If a,b,c are interior angles of tra abc, then prove that cosec {a+b/2}= sec {c/2} |
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Answer» AnswerGiven A,B,C are the interior angles of △ABC⟹A+B+C=180 ∘ ⟹A+B=180 ∘ −CLHS=cosec( 2A+B ) =cosec( 2180 ∘ −C ) =cosec(90 ∘ − 2C ) =SEC 2C =RHS |
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