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If `a, b, c `are positive real numbers such that `ab^2c^3= 64` then minimum value of `1/a+2/b+3/c` is equal to |
Answer» Given `ab^2c^3=64` now we have to find minimum value of `1/a+2/b+3/c`. this can be done by the concept fo` AM>=GM`, where AM and GM are the arithmetic and geometric mean. Let there be 6 terms that are`1/a,1/b,1/b,1/c,1/c,1/c`, applying `AM>=GM` on them. we get, `(1/a+2/b+3/c)/6>=(1/(ab^2c^3))^(1/6)` `(1/a+2/b+3/c)/6>=3` hence minimum value is 3. |
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