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If a,b,c are three distinct numbers in G.P., b,c,a are in A.P and a,bc, abc, in H.P then the possible value of b isA. `3+4sqrt(2)`B. `3-4 sqrt(2)`C. `4+ 3 sqrt(2)`D. `4-3sqrt(2)` |
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Answer» Correct Answer - C::D Let `a=A/r,b=A and C=Ar` Now b,c,a are in A.P.. `therefore2c=a+b` `rArr2Ar=A/r+A` `rArr2r^(2)-r-1=0` `rArrr=1 or r=-1/2` Sine a,b, are distinctt, `r=-1/2` `thereforea=-2A,b=A,c=-A/2` a,bc,abc are in H.P. `therefore 1/a,1/(bc),1/(abc)` are in A.P. `rArr 2/(bc)=1/(abc)+1/a` `rArr-4/A^(2=1/A^(3)-1/(2A)` `rArr-4/(A^(2))=(2-A^(2))/(2A^(3))` `rArr-8A=2-A^(2)` `rArrA^(2)-8A-2=0` `rArrA=pm3sqrt2` |
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