If a, b, c are three distinct real numbers in G.P. and a + b + c = xb,

1.	If a, b, c are three distinct real numbers in G.P. and a + b + c = xb, then prove that either x < – 1 or x > 3.
Answer» Let a be the first term of GP with r being the common ratio. ∴ b = ar …(1) c = ar² …(2) Given, (a + b + c) = xb ⇒ (a + ar + ar²) = x(ar) ⇒ a(1 + r + r²) = ar ⇒ (1 + r + r²) = xr ⇒ r² + (1 – x)r + 1 = 0 As r is a real number ⇒ Both solutions are real. So discriminant of the given quadratic equation D ≥ 0 As, D ≥ 0 ⇒ (1 – x)² – 4(1)(1) ≥ 0 ⇒ x² – 2x – 3 ≥ 0 ⇒ (x – 1)(x – 3) ≥ 0 ∴ x < – 1 or x > 3 …proved

If a, b, c are three distinct real numbers in G.P. and a + b + c = xb, then prove that either x < – 1 or x > 3.

Answer»

Let a be the first term of GP with r being the common ratio.

∴ b = ar …(1)

c = ar² …(2)

Given, (a + b + c) = xb

⇒ (a + ar + ar²) = x(ar)

⇒ a(1 + r + r²) = ar

⇒ (1 + r + r²) = xr

⇒ r² + (1 – x)r + 1 = 0

As r is a real number ⇒ Both solutions are real.

So discriminant of the given quadratic equation

D ≥ 0 As, D ≥ 0

⇒ (1 – x)² – 4(1)(1) ≥ 0

⇒ x² – 2x – 3 ≥ 0

⇒ (x – 1)(x – 3) ≥ 0

∴ x < – 1 or x > 3 …proved