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If A + B + C = π, then \(\frac{tanA +tanB+tanC}{tanA\,tanB\,tanC}\) is equal toA. tan A tan B tan C B. 0 C. 1 D. None of these |
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Answer» A + B = π - C \(\frac {tanA+tanB}{1-tanAtanB}\) = - tan C tan A + tan B + tan C = tanA tanB tanC \(\frac{tanA +tanB+tanC}{tanA\,tanB\,tanC}\) = 1 |
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