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If `A+B+C=pi`, prove that : `sin (B+C-A) + sin (C+A-B) + sin (A+B-C)=4sinA sinB sinC` |
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Answer» `LHS=sin(A+B+C-2A)+sin(A+B+C-2B)-sin(A+B+C-2C)` `=sin (pi-2A)+sin(pi-2B)-sin(pi-2C)` `=sin2A+sin2B-sin2C.` |
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