1.

If  a = b = c, prove that the points (a, a2), (b,b2),(c, c2) can never be collinear.

Answer»

Area of the triangle having vertices (x1, y1), (x2, y2) and (x3, y3) is given by

Area of △ = \(\frac{1}2[x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1-y_2)]\)

For points to be collinear, the Area enclosed by them should be equal to 0 

∴ For given points,

Area = \(\frac{1}2[a(b^2 - c^2) + b(c^2- a^2) + c(a^2-b^2)]\)

Area = \(\frac{1}2\) |(b – c)(a - b)(c – a)| 

Area ≠ 0 

Also it is given that a ≠ b ≠ c,

Hence area of triangle made by these points is never zero. Hence given points are never collinear.



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