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If a = b cos \(\frac{2π}3\) = c cos\(\frac{4π}3\),then write the value of ab + bc + ca. |
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Answer» a = b cos \(\frac{2π}3\) = c cos\(\frac{4π}3\) = k a = k b—2k c=-2k ab + bc + ca.= 0 |
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