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If (a/b)^x-1=(b/a)^x-3 , find the value of 'x'. (assume a is not equal to b) |
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Answer» -by-step explanation:f(G(X))=a(bx+a)+b=abx+a^2+bg(f(x))=b(ax+b)+aTherefore f(g(x))−g(f(x))=abx+a^2+b−(abx+b^2+a)=a^2−b^2+b−a=(a−b)(a+b−1)Since it is a constant FUNCTION(a−b)(a+b−1)=28(a−b)(a+b−1)=4(7)HENCE a−b=4a+b=8a=6 and b=2Hence ab=12Also(a−b)(a+b−1)=(1)(28)a−b=1a+b=29a=15 and b=14Therefore ab=14(15)=210 |
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