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If a bar magnet moment M is freely suspended in a uniform magnetic field of strength field of strength B, then the work done in rotating the magent through an angle `theta` isA. `MB(1-sin theta)`B. `MBsin theta`C. `MB cos theta`D. `MB(1-cos theta)` |
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Answer» Work done is rotating the magnet through an angle `theta` from initial position `(i.e.,theta_(1)=0^(@))` is given by `W=MB(cos theta _(1)-cos theta)=MB(cos 0^(@)-cos theta)=MB(1-costheta)` |
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