1.

If a bar magnet of magnetic moment 'm' is freely suspended in a uniform magnetic field B, the work done in rotating the magnet through an angle thete is

Answer»

`mB(1- sin THETA)`
`mB sin theta`
`mB COS B`
`mB(1-costheta)`

SOLUTION :Work done W = `mB[cos theta_1 - cos theta_2]`
As here `theta_1 = 0^@ and theta_2 = theta` , HENCE W = `mB[cos 0^@ - cos theta] = mB(1-cos theta)`


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