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If a bar magnet of magnetic moment 'm' is freely suspended in a uniform magnetic field B, the work done in rotating the magnet through an angle thete is |
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Answer» `mB(1- sin THETA)` As here `theta_1 = 0^@ and theta_2 = theta` , HENCE W = `mB[cos 0^@ - cos theta] = mB(1-cos theta)` |
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