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If a body of mass 200 g falls a height 200 m and its total P.E. is converted into K.E. at the point of contact of the body with earth surface. Then what is the decrease in P.E. of the body at the contact. `(g=10m//s^(2))`A. 900 JB. 600 JC. 400 JD. 200 J |
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Answer» Correct Answer - C (c ) Mass of the body, m=200 g`=200xx10^(-3)`kg Height of body, h=200 m Potential energy, U=mgh`=200xx10^(-3)xx10xx200=400 J` Therefore, Decrease in potential energy at the surface =400 J. |
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