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If a bodyof mass 1000 gm is tied to free end of string of length 100 cm and whirled in a horizontal circle in a second, then the tecsion in the string will beA. `4pi^(2) N`B. `2pi^(2) N`C. `3pi^(2)N`D. `pi^(2)N` |
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Answer» Correct Answer - A `T=c.p.f.=m r omega ^(2)=m r ((2pi)/(T))^(2)` |
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