if a bus accelerates from rest from for time T1 at a constant rate of Alpha and then retards at a constant rate of Beta for time T2 and comes at comes to rest then T1 buy theta is equals to

if a bus accelerates from rest from for time T1 at a constant rate of

1.	if a bus accelerates from rest from for time T1 at a constant rate of Alpha and then retards at a constant rate of Beta for time T2 and comes at comes to rest then T1 buy theta is equals to
Answer» INITIAL velocity of bus (u) = 0m−1velocity of bus after t_1 sec = vt1ms−1velocity of bus after t2 sec = vt2ms−1 = 0ms−1 (as it comes to rest)acceleration = αms−2deceleration = ßms−2v=u+atFor 1st part of motion (acceleration)vt1=u+α∗t1vt1=α∗t1 ————(1)For 2ND part of motion (DECELRATION)vt2=v1−ß∗t20=v1−ß∗t2 ————(2)from (1) and (2)0=α∗t1−ß∗t2α∗t1=ß∗t2t1t2=ßαhope it helps