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If a C.E. stage has a load Rl and transconductance gm, what is the factor by which the capacitance between the base and the collector at the output side gets multiplied?(a) 1 + 1/gmRl(b) 1 – 1/gmRl(c) 1 + 2/gmRl(d) 1 – 2/gmRlI got this question in class test.The question is from Effect of Various Capacitors on Frequency Response topic in section Transistor Frequency Response of Analog Circuits

Answer»

Right OPTION is (a) 1 + 1/gmRl

The best I can EXPLAIN: The low FREQUENCY response of the C.E. stage is gmRl. By the application of miller effect, we FIND that the capacitance between the base and the collector, looking from the OUTPUT side, will be increased by a factor of 1 + 1/gmRl. Hence, the correct option is 1 + 1/gmRl.



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