If a C.E. stage with early effect has a load Rl and transconductance gm, what is the factor by which the capacitance between the base and the collector at the output side, gets multiplied?(a) 1 + 2/gm*(Rl || ro)(b) 1 – 1/gm*(Rl || ro)(c) 1 + 1/gm*(Rl || ro)(d) 1 – 2/gm*(Rl || ro)This question was addressed to me in my homework.Query is from Effect of Various Capacitors on Frequency Response topic in chapter Transistor Frequency Response of Analog Circuits

If a C.E. stage with early effect has a load Rl and transconductance g

1.	If a C.E. stage with early effect has a load Rl and transconductance gm, what is the factor by which the capacitance between the base and the collector at the output side, gets multiplied?(a) 1 + 2/gm(Rl \|\| ro)(b) 1 – 1/gm(Rl \|\| ro)(c) 1 + 1/gm(Rl \|\| ro)(d) 1 – 2/gm(Rl \|\| ro)This question was addressed to me in my homework.Query is from Effect of Various Capacitors on Frequency Response topic in chapter Transistor Frequency Response of Analog Circuits
Answer» The correct choice is (c) 1 + 1/gm(Rl \|\| RO) The explanation: If the early effect is considered, the low frequency response of the C.E. stage becomes gm(Rl \|\| ro). Thereby, MILLER APPROXIMATION shows that the capacitance between the BASE and the collector, looking from the output SIDE, will be increased by a factor of 1 + 1/gm(Rl \|\| ro). Hence the correct option is 1 + 1/ gm(Rl \|\| ro).

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