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If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s, it covers a distance of: |
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Answer» 20 m `v=144 KMH^(-1)=40MS^(-1),u=0` `:. A=(v)/(t)=(40)/(20)=2 ms^(-2)` Now `s=0+(1)/(2)xx2xx(20)^(2)=400m` |
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