1.

If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s, it covers a distance of:

Answer»

20 m
1440 m
400 m
2980 m

Solution :Here APPLYING v=u+at
`v=144 KMH^(-1)=40MS^(-1),u=0`
`:. A=(v)/(t)=(40)/(20)=2 ms^(-2)`
Now `s=0+(1)/(2)xx2xx(20)^(2)=400m`


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