InterviewSolution
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InterviewSolution
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If a coin is tossed n times, then find the probability that the head appears odd number of times. |
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Answer» Total number of cases = `2^(n)` If head appears odd number of times (1, 3, 5, … times), then Number of favourable ways = `(.^(n)C_(1) + .^(n)C_(3) + .^(n) C_(5) +...) = 2^(n-1)` `therefore` Required probability = `(2^(n-1))/(2^(n)) = (1)/(2)` |
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