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    				| 1. | if `A(cosalpha,sinalpha),B(sinalpha,-cosalpha),C(1,2)` are the vertices of `DeltABC`,then as `alpha` Find the locsus of its centroid. | 
| Answer» Let (h,k) be the triangle . Then, `h=(cosalpha+sinalpha+1)/(3)` and `k=(sinalpha-cosalpha+2)/(3)` or `3h-1=cosalpha+sinalpha` and `3k-2=sinalpha-cosalpha` Squareing and adding, we get ` (3h-1)^2+(3k-2)^2=2` or `9(h^2+k^2)-6h-12k+3=0` or `3(h^2+k^2)-2h-4k+1=0` Therefore the locus of the centroid is `3(x^2+y^2)-2x-4y+1=0` . | |