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If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons flow through the wire? |
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Answer» Solution :Q (COULOMBS)=I(ampere)`XXT(sec)=(0.5" ampere")xx(2xx60xx60s)=3600C` A flow of 1 F, i.e., 96500 C is equivaelent to flow of 1 mole of ELECTRONS, i.e., `6.02xx10^(23)` electrons `therefore3600C` is EQUIVALENT to flow of electrons `=(6.02xx10^(23))/(96500)xx3600` `=2.246xx10^(22)` electrons. |
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