Saved Bookmarks
| 1. |
If a cylinder at NTP contains a gas and it can withstand a temperature of 473K then pressure inside the cylinder at the time of explosion will be? |
| Answer» Solution :Using Gay Lusaac’s Law `(P_(1))/(T_(1)) = (P_(2))/(T_(2))` . So, as per the data GIVEN `(1)/(273) = (P_(2))/(473) IMPLIES P_(2)= 1.732"ATM"` at the time of EXPLOSION. | |