1.

If a diamond plate of refractive index 2.5 is introduced in path of second beam to bring the central band to original position then its thickness is

Answer»

`1 xx 10^(-5) cm`
`2 xx 10^(-5) cm`
`3 xx 10^(-5) cm`
`1 xx 10^(-5) cm`

SOLUTION :Now `(mu_(d) -1)t.(D)/(d) = (lambdaD)/(d) ` here `mu_(d) = 2.5`
`THEREFORE t = (lambda)/(mu_(d) -1) = (6000 xx 10^(-8))/(2.5 - 1) = 4 xx 10^(-5)` cm.


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