If a dipositve ion of an element 'X' consists of 12 protins and 12 neutrons and another dipositve ion of an element 'Y' consists of 18 electrons and twice the number of electrons of dipositive ion X is the number of neutrons of Y . Thenthe mass numbers wouldbe in the ratio of

If a dipositve ion of an element 'X' consists of 12 protins and 12 neu

1.	If a dipositve ion of an element 'X' consists of 12 protins and 12 neutrons and another dipositve ion of an element 'Y' consists of 18 electrons and twice the number of electrons of dipositive ion X is the number of neutrons of Y . Thenthe mass numbers wouldbe in the ratio of
Answer» ` 1 : 2 ` `3:5` `12:19` `2 : 3` Solution :In`X^(+2)`, Number of protons = 12 (Z) NEUTRONS = 12 Number of electrons = 10 Mass number (A) = 12 + 12 = 24 In `Y^(+2)` electrons are there. In Y 20 electrons or 20 protons (Z) are there . Mass number (A) = 20 +20 = 40 `:.`Ratio of mass number`=A_(x) "" : "" A_(y)` `{:(24,:,40),(3,:,5):}`