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If a disc slides from top to bottom of an inclined plane, it takes time t_(1). If it rolls, it takes time t_(2). Now, (t_(2)^(2))/(t_(1)^(2)) is

Answer»

`(1)/(2)`
`(2)/(3)`
`(3)/(2)`
`(2)/(5)`

Solution :Here the time `t_(1)=SQRT((2l)/(gsintheta))`
Also the rolling time `t_(2)=sqrt((3l)/(gsintheta))`
`THEREFORE (t_(2)^(2))/(t_(1)^(2))=(3)/(2)`


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