1.

If a electric field of magnitude 570 N C^(-1), is applied in the copper wire. find the acceleration experienced by the electron.

Answer»

SOLUTION :`E=570NC^(-1),r=1.6xx10^(-19)`C,
`m=9.11xx10^(-31)kg` and a=?
F=ma=eE
`impliesa=(eE)/m=(570xx1.6xx10^(-19))/(9.11xx10^(-31))=1.001xx10^(14)ms^(-2)`


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