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If a electric field of magnitude 570 N C^(-1), is applied in the copper wire. find the acceleration experienced by the electron. |
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Answer» SOLUTION :`E=570NC^(-1),r=1.6xx10^(-19)`C, `m=9.11xx10^(-31)kg` and a=? F=ma=eE `impliesa=(eE)/m=(570xx1.6xx10^(-19))/(9.11xx10^(-31))=1.001xx10^(14)ms^(-2)` |
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