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If a figure, the linear velocity `vecv` in terms of polar coordinate is A. `vecv=vecir cos omegat+vec jr sin omega t`B. `vecv=vecir sin omegat+vec jr cos omega t`C. `vecv=(+vecir sin omegat+vec jr cos omega t)omega`D. `vecv=-vecir omega sin omegat+vec jr omega cos omega t`

Answer» Correct Answer - D
`vec r =r cos omega t vec I + vec j er omega t vec j `
` (dvec r )/(dt)=- r omega sin omega t + vec j cos omega t `


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