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If a graph is plotted between `T^(2) and r^(3)` for a planet, then its slope will be be (where `M_(S)` is the mass of the sun)A. `(4pi^(2))/(GM_(S))`B. `(GM_(S))/(4pi)`C. `4piGM_(S)`D. `GM_(S)` |
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Answer» Correct Answer - A (a) Time period of a revolution of a planet, `T=( 2pi r)/(v)=(2pi r)/(sqrt((GM_(S))/(r )))=(2 pi r^(3//2))/(sqrt(GM_(S))` where `M_(S)` is the mass of the sun Squaring both sides, we get `T^(2)=(4 pi^(2) r^(3))/(GM_(S))` The graph between `T^(2)` and `r^(3)` is a straight line whose slope is is `(4 pi^(2))/(GM_(S))`. |
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