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If `a gt 0`, the least value of `(a^3+a^2+a+1)^2` isA. `64a^2`B. `16a^4`C. `16a^3`D. none of these |
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Answer» Correct Answer - C We have `(a^(3) + 1)/(2) ge sqrt(a^(3) xx 1)` and `(a^(2) + a^(1))/(2) ge sqrt(a^(2) a^(1))` Adding, we get `(a^(3) + a^(2) + a + 1)/(2) ge 2 sqrt(a^(3))` |
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