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If `A` is a square matrix of order `3` such that `|A|=2`, then `|(adjA^(-1))^(-1)|` isA. `1`B. `2`C. `4`D. `8` |
Answer» Correct Answer - C `(c )` `|adjA^(-1)|=|A^(-1)|^(2)=(1)/(|A|^(2))` `|(adjA^(-1))^(-1)|=(1)/(|adjA^(-1)|)=|A|^(2)=2^(2)=4` |
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