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If A is non-singular square matrix such that A-1 = \(\begin{bmatrix} 5 &3 \\[0.3em] -2 & -1 \\[0.3em] \end{bmatrix}\) then find (AT )–1. |
Answer» We have, (AT)-1 = (A-1)T = \(\begin{bmatrix} 5 &3 \\[0.3em] -2 & -1 \\[0.3em] \end{bmatrix}^T\) = \(\begin{bmatrix} 5 &-2 \\[0.3em] 3 & -1 \\[0.3em] \end{bmatrix}.\) |
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