If a letter is chosen at random from the English alphabets {a, b,…,

1.	If a letter is chosen at random from the English alphabets {a, b,…, z} then the probability that the letter chosen precedes x ___(1) \(\frac{12}{13}\)(2) \(\frac{1}{13}\)(3) \(\frac{23}{26}\)(4) \(\frac{3}{26}\)
Answer» (3) \(\frac{23}{26}\) \(=1-\frac{3}{26}=\frac{23}{26}\)

If a letter is chosen at random from the English alphabets {a, b,…, z} then the probability that the letter chosen precedes x ___(1) \(\frac{12}{13}\)(2) \(\frac{1}{13}\)(3) \(\frac{23}{26}\)(4) \(\frac{3}{26}\)

Answer»

(3) \(\frac{23}{26}\)

\(=1-\frac{3}{26}=\frac{23}{26}\)

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If a letter is chosen at random from the English alphabets {a, b,…, z} then the probability that the letter chosen precedes x ___(1) \(\frac{12}{13}\)(2) \(\frac{1}{13}\)(3) \(\frac{23}{26}\)(4) \(\frac{3}{26}\)

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