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If a light of wavelength 4950 Å is viewed as a continuous flow of photons, what is the energy of each photon in eV ? (Given h = 6.6 xx 10^(-34) "Js, c =" 3 xx 10^(8) ms^(-1)) |
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Answer» SOLUTION :Here `lambda = 4950 Å = 4950 XX 10^(-10) m` ENERGY of each photon, `E =(hc)/(lambda) = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(4950 xx 10^(-10)) = 4 xx 10^(-19)J` `= (4 xx 10^(-19))/(1.6 xx 10^(-19)) eV` E = 2.5 eV |
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