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If a light of wavelength 4950 A^@is viewed as a continuous flow of photons, what is the energy of each photon in eV? Given h = 6.6 xx 10^(-34) Js, C=3 xx 10^8 ms^(-1)? |
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Answer» SOLUTION :Here `lambda = 4950 A^@ = 4950 xx 10^-10 m` Energy of each photon `E= (HC)/lambda = (6.6 xx 10^-34 xx 3 xx 10^8)/(4950 xx 10^-10) = 4.0 xx 10^-19` `= (4.0 xx 10^-19)/(1.6 xx 10^-19) = e V = 2.5 e V |
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