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If a line makes an angle of 60°, 150°, 45° with the positive x, y, z-axis respectively, find its direction cosines.(a) –\(\frac{1}{2},-\frac{\sqrt{3}}{2},\frac{1}{\sqrt{2}}\)(b) –\(\frac{1}{2},-\frac{\sqrt{3}}{2},-\frac{1}{\sqrt{2}}\)(c) \(\frac{1}{2},-\frac{\sqrt{3}}{2},\frac{1}{\sqrt{2}}\)(d) \(\frac{1}{2},\frac{\sqrt{3}}{2},-\frac{1}{\sqrt{2}}\)I have been asked this question in class test.This is a very interesting question from Direction Cosines and Direction Ratios of a Line in portion Three Dimensional Geometry of Mathematics – Class 12

Answer»

Correct answer is (c) \(\frac{1}{2},-\frac{\SQRT{3}}{2},\frac{1}{\sqrt{2}}\)

Easiest explanation: Let l, m, N be the direction COSINES of the line.

We KNOW that, if α, β, γ are the ANGLES that the line makes with the x, y, z-axis respectively, then

l=cos⁡α=cos⁡60°=\(\frac{1}{2}\)

m=cos⁡β=cos⁡150°=-\(\frac{\sqrt{3}}{2}\)

n=cos⁡γ=cos⁡45°=\(\frac{1}{\sqrt{2}}\).


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