1.

If a man at the equator would weigh `(3//5)`th of his weight, the angular speed of the earth isA. `sqrt(2/5 g/R)`B. `sqrt(g/R)`C. `sqrt(R/g)`D. `sqrt(2/5 R/g)`

Answer» Correct Answer - A
`3/5mg=mg=mRomega^(2)`
`=omega^(2)=g-3/5impliesomega=sqrt(2/5g/R)`


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