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If A Man Travels With 5/6th Of His Usual Speed, He Is Late By 15 Mins. What Is The Usual Time Taken To Travel ? |
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Answer» SUPPOSE man's usual speed = s, and usual time = t So distance = speed *time ==> d= s*t If he TRAVELS with 5/6th of his usual speed which is = s*5/6 And time= (t+15) and distance, d = (s*5/6)*(t+15) {as distance will be same} s*t = (s*5/6)*(t+15) t= (5t+75)/6 t= 75 MIN. Suppose man's usual speed = s, and usual time = t So distance = speed *time ==> d= s*t If he travels with 5/6th of his usual speed which is = s*5/6 And time= (t+15) and distance, d = (s*5/6)*(t+15) {as distance will be same} s*t = (s*5/6)*(t+15) t= (5t+75)/6 t= 75 min. |
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