1.

If A Man Travels With 5/6th Of His Usual Speed, He Is Late By 15 Mins. What Is The Usual Time Taken To Travel ?

Answer»

SUPPOSE man's usual speed = s, and usual time = t 

So distance = speed *time ==> d= s*t

If he TRAVELS with 5/6th of his usual speed which is = s*5/6

And time= (t+15) and distance, d = (s*5/6)*(t+15) {as distance will be same} 

s*t = (s*5/6)*(t+15) 

t= (5t+75)/6

t= 75 MIN.

Suppose man's usual speed = s, and usual time = t 

So distance = speed *time ==> d= s*t

If he travels with 5/6th of his usual speed which is = s*5/6

And time= (t+15) and distance, d = (s*5/6)*(t+15) {as distance will be same} 

s*t = (s*5/6)*(t+15) 

t= (5t+75)/6

t= 75 min.



Discussion

No Comment Found