The Ages Of Two Persons Are In The Ratio 5: 7. Eighteen Years Ago The

1.	The Ages Of Two Persons Are In The Ratio 5: 7. Eighteen Years Ago Their Ages Were In The Ratio 8:13. Find Their Present Ages ?
Answer» Let the required AGES be 5x and 7X 18 YEARS AGO their age RATIOS 5x−187x−18=813 65x−13×18=8×7x−8×18 65x-234=56x-144 65x-56x=234-144 9x=90 x=10 Thus the ages are 5x=5×10=50years 7x=7×10=70 years Let the required ages be 5x and 7x 18 years ago their age ratios 5x−187x−18=813 65x−13×18=8×7x−8×18 65x-234=56x-144 65x-56x=234-144 9x=90 x=10 Thus the ages are 5x=5×10=50years 7x=7×10=70 years

The Ages Of Two Persons Are In The Ratio 5: 7. Eighteen Years Ago Their Ages Were In The Ratio 8:13. Find Their Present Ages ?

Answer»

Let the required AGES be 5x and 7X

18 YEARS AGO their age RATIOS

5x−187x−18=813

65x−13×18=8×7x−8×18

65x-234=56x-144

65x-56x=234-144

9x=90

x=10

Thus the ages are 5x=5×10=50years

7x=7×10=70 years

Let the required ages be 5x and 7x

18 years ago their age ratios