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InterviewSolution
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If a metal forms a FCC lattice with unit edge length 500 pm. Calculate the density of the metal if its atomic mass is 110.(a) 2923 kg/m^3(b) 5846 kg/m^3(c) 8768 kg/m^3(d) 1750 kg/m^3I had been asked this question by my school teacher while I was bunking the class.Question is from Solid State in section Solid State of Chemistry – Class 12 |
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Answer» RIGHT option is (b) 5846 kg/m^3 The best explanation: Given, Edge length (a) = 500 pm = 500 X 10^-12 m Atomic mass (M) = 110 g/mole = 110 x 10^-3 kg/mole Avogadro’s number (NA) = 6.022 x 10^23/mole z = 4 atoms/cell The density, d of a metal is given as d=\(\frac{ZM}{a^3N_A}\) On substitution, d=\(\frac{4 \times 110 \times 10^{-3}}{(500 \times 10^{-12})^3 \times 6.022 \times 10^{23}}\)=5846 kg/m^3. |
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