If `(A)/(mu_(0))` has the dimensions `[MLT^(-4)]` what is A?A. square of electric fluxB. square of magnitic fluxC. square of electric fieldD. square of energy

If `(A)/(mu_(0))` has the dimensions `[MLT^(-4)]` what is A?A. square

1.	If `(A)/(mu_(0))` has the dimensions `[MLT^(-4)]` what is A?A. square of electric fluxB. square of magnitic fluxC. square of electric fieldD. square of energy
Answer» Correct Answer - c `[(A)/(mu_(0))]= [(epsilon_(0)A)/(epsilon_(0)mu_(0))]= ([epsilon_(0)d])/(1//"speed of light"]^(2)` `= [ML^(2)T^(-2)]` (Given) `[epsilon_(0) A] = [ML^(-1)T^(-2)] = ([ML^(2)T^(-2)])/([L^(2)])` So `epsilon_(0)A` is the energy per volume Thus A should be `E^(2)`

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If `(A)/(mu_(0))` has the dimensions `[MLT^(-4)]` what is A?A. square of electric fluxB. square of magnitic fluxC. square of electric fieldD. square of energy

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