InterviewSolution
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InterviewSolution
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If `(a^n+b^n)/(a^(n-1)+b^(n-1))` is the AM between a and b, then the value of n is |
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Answer» Correct Answer - B Since `(a^(n)+b^(n))/(a^(n-1)+b^(n-1))` is Am of a and b. `:." "(a^(n)+b^(n))/(a^(n-1)+b^(n-1))=(a+b)/(2)` `rArr" "2a^(n)+2b^(n)=a^(n)+b^(n)+ab^(n-1)+a^(n-1)b` `rArr" "a^(n-1)(a-b)=b^(n-1)(a-b)` `rArr" "((a)/(b))^(n-1)=1rArrn-1=0rArrn=1` ALITER We have, `(a^(n)+b^(n))/(a^(n-1)+b^(n-1))(a+b)/(2)` `rArr" "(a^(n)+b^(n))/(a^(n-1)+b^(n-1))=(a+b)/(2)=(a^(1)+b^(1))/(a^(0)+b^(0))` On comparing the two sides, we obtain n=0. |
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