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If a number is decreased by 10%, it becomes 108. By how much percent, thenumber is to be increased so that the number becomes 144?

Answer» <p>Let the Number be xwhen x is decreased by 10%, it becomes 108</p><p>=&gt; x - 10% of x = 108=&gt; x - (10/100)×x = 108=&gt; x(1 - 10/100) = 108=&gt; x(90/100) = 108=&gt; 90x = 108×100=&gt; x = 120</p><p>Therefore,Number is 120</p><p>120 + y% of 120 = 144=&gt; y% of 120 = 144-120=&gt; (y/100)×120 = 24=&gt; y/10 = 2=&gt; y = 20%</p><p>Therefore, the number 120 when increased by 20% gives 144</p> <p>Let the Number be xwhen x is decreased by 10%, it becomes 108</p><p>x - 10% of x = 108</p><p>x - (10/100)×x = 108</p><p>x(1 - 10/100) = 108</p><p>x(90/100) = 108</p><p>90x = 108×100</p><p>x = 120</p><p>Original Number is 120</p><p>when number is increased by 20%</p><p>120 + y% of 120 = 144</p><p> y% of 120 = 144-120</p><p> (y/100)×120 = 24</p><p>y = (24/120)100</p><p>y = 20%</p><p>Therefore, the number 120 when increased by 20% gives 144</p><p>HENCE, The required number = 120 ANS. </p>


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