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If `A={:[(p,0),(0,p)]:}" then "A^(n+1)` is _________ .A. `{:[(p,0),(0,p)]:}`B. `{:[(p^(n+1),0),(0,p^(n+1))]:}`C. `{:[(np,0),(0,np)]:}`D. None of these |
Answer» Correct Answer - B Given `A={:[(p,0),(0,P)]:}` `A=P={:[(1,0),(0,1)]:}` `A=PI` `A^(n+1)=P^(n+1)xxI^(n+1)=P^(n+1)I(becauseI^(n)=I)` `=P^(n+1){:[(1,0),(0,1)]:}={:[(p^(n+),0),(0,P^(n+1))]:}`. |
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