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If [a =π/{(2 ^n ) + 1)]prove that [(2^n) cos a cos 2a cos 2²a cos 2³a. cos (2^n) - 1] = 1 |
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Answer» LHS=( 2sinA 2sinAcosAcos2Acos4Acos8A ) =( 2×2sinA 2×sin2Acos2Acos4Acos8A ) =( 2×4sinA 2×sin4Acos4Acos8A ) =( 2×8sinA 2×sin8Acos8A ) =( 16sinA sin16A )=RHS |
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