1.

If [a =π/{(2 ^n ) + 1)]prove that [(2^n) cos a cos 2a cos 2²a cos 2³a. cos (2^n) - 1] = 1​

Answer»

ANSWER:

LHS=(

2sinA

2sinAcosAcos2Acos4Acos8A

)

=(

2×2sinA

2×sin2Acos2Acos4Acos8A

)

=(

2×4sinA

2×sin4Acos4Acos8A

)

=(

2×8sinA

2×sin8Acos8A

)

=(

16sinA

sin16A

)=RHS



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