1.

If a particle is at rest with three velocities of 14 units, 16 units and 26 units on it, then the angle between the directions of the two smaller velocities is :

Answer»

30°
60°
120°
150°

Solution :As the PARTICLE is at REST then
`|R|=sqrt(A^(2) + B^(2)+2ABcostheta)`
`(26)^(2)=(14)^(2) + (16)^(2) + 2xx16 xx14costheta`
On solving `costheta=1/2` or `theta=60^@`


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