If a particle is moving such that the velocity acquired is proportional to the square root of the distance covered, then its acceleration isA. a constantB. `prop s^(2)`C. `prop(1)/(s^(2))`D. `prop s`

If a particle is moving such that the velocity acquired is proportiona

1.	If a particle is moving such that the velocity acquired is proportional to the square root of the distance covered, then its acceleration isA. a constantB. `prop s^(2)`C. `prop(1)/(s^(2))`D. `prop s`
Answer» Correct Answer - A Let v be the velocity of the particle when the distance covered is s. Then, `v prop sqrt(s)` [Given] `implies v = lambda sqrt(s)` `implies (dv)/(ds)=(lambda)/(2sqrt(s))` `implies v(dv)/(ds)=(lambdav)/(2sqrt(s)) = (lambda^(2))/(2)` = constant. Hence, the acceleration is constant.

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If a particle is moving such that the velocity acquired is proportional to the square root of the distance covered, then its acceleration isA. a constantB. `prop s^(2)`C. `prop(1)/(s^(2))`D. `prop s`

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