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The weight W of a certain stock of fish is given by W = nw, where n is the size of stock and w is the average weight of a fish. If n and w change with time t as n = `2t^(2)+3` and `w=t^(2)-t+2`, then the rate of change of W with respect to t at t = 1, isA. 1B. 13C. 5D. 8 |
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Answer» Correct Answer - B We have, `W=nw, n=2t^(2)+3 and w=t^(2)-t+2` `therefore (dV)/(dt)=(dn)/(dt)w+n(dw)/(dt),(dn)/(dt)=4t,(dW)/(dt)=2t-1` At t=1, we get `n=5,w=2, (dn)/(dt)=4, (dw)/(dt)=1` Hence, `((dW)/(dt))_(t=1)=4xx2+5xx1=13` |
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